Elizabeth Howe

Elizabeth Howe

Female 1702 - 1740  (37 years)

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  • Name Elizabeth Howe  [1, 2
    Birth 24 Jul 1702  Sudbury, Middlesex, Massachusetts, USA Find all individuals with events at this location  [1, 2
    Gender Female 
    Death 27 Apr 1740  Framingham, Middlesex, Massachusetts, USA Find all individuals with events at this location  [1, 2
    • Age: 37
    Person ID I25795  A Tree Called Smith
    Last Modified 2 Mar 2023 

    Family John Butler, Jr,   b. 1 Mar 1700, Lynn, Essex, Massachusetts, USA Find all individuals with events at this locationd. 25 Jan 1747, Framingham, Middlesex, Massachusetts, USA Find all individuals with events at this location (Age 46 years) 
    Marriage 1726  Framingham, Middlesex, Massachusetts, USA Find all individuals with events at this location  [1
    Children 
     1. Captain Joseph Butler,   b. 15 Aug 1734, Framingham, Middlesex, Massachusetts, USA Find all individuals with events at this locationd. 27 Feb 1784, Concord, Middlesex, Massachusetts, USA Find all individuals with events at this location (Age 49 years)  [natural]
    Family ID F3307  Group Sheet  |  Family Chart
    Last Modified 2 Mar 2023 

  • Event Map
    Link to Google MapsBirth - 24 Jul 1702 - Sudbury, Middlesex, Massachusetts, USA Link to Google Earth
    Link to Google MapsMarriage - 1726 - Framingham, Middlesex, Massachusetts, USA Link to Google Earth
    Link to Google MapsDeath - 27 Apr 1740 - Framingham, Middlesex, Massachusetts, USA Link to Google Earth
     = Link to Google Earth 

  • Sources 
    1. [S4] Ancestry Family Trees, (Name: Online publication - Provo, UT, USA: Ancestry.com. Original data: Family Tree files submitted by Ancestry members.;), Database online.

    2. [S425] Ancestry.com, U.S., Sons of the American Revolution Membership Applications, 1889-1970, (Name: Ancestry.com Operations, Inc.; Location: Provo, UT, USA; Date: 2011;), SAR Membership Number: 98188.
      Record for Captain Joseph Butler
      http://search.ancestry.com/cgi-bin/sse.dll?db=sarmemberapps&h=1066725&indiv=try